tolong bantu saya!!!
Jawaban:
titik berat = luas segiempat - luas segitiga kosong
segiempat
A1 = pxl = 6x4 = 24
x1 = ½p = 3
y1 = ½l = 2
segitiga
A2 = ½ alas x tinggi = ½ x 4 x 3 = 6
x2 = 1/3 tinggi = 1/3 x 3 = 1
y2 = ½ alas = 2
titik berat
x = (A1x1 - A2x2)/(A1-A2)
x = (24x3 - 6x1)/(24-6)
x = 66/18 = 3,67
y = (A1y1 - A2y2)/(A1-A2)
y = (24x2 - 6x2)/(24-6)
y = 36/18 = 2
Penjelasan:
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